Superposition is Not Uncertainty — It’s Unresolved Causal Depth

This work is a direct application of the Alpha–Beta–Omega–Sigma (ABOS) Law — Version 14
(10.5281/zenodo.18002324), a geometric-first framework where space, time, and causality emerge from the conflict of incompatible symmetries 3, 4, 5.
In ABOS, “superposition” is not ontological ambiguity — it is unresolved causal depth: a real choice has been made, but its geometric signature (encoded in θ, Δₛ, and the Ω-grid) remains hidden until observation completes the projection.
What follows is the quantum interpretation of that principle.

Classical Preview: The Janibekov Effect as Ωₕ-Cascade in Rigid-Body Dynamics   
Before addressing quantum superposition, we present a deterministic, classical  system where ABOS geometry manifests with sub-0.1% precision: the Janibekov effect  (intermediate-axis theorem). In freely rotating rigid bodies, the angular velocity profile exhibits a strict biphasic pattern—growth to peak → rapid flip → decay to plateau—whose temporal ratio  
[
X_+X_- = _h 2.677018851
]  
matches the analytical  Ωₕ from ABOS-14 (Section II.4). No fitting. No degrees of freedom. The convergence of “reverse Ωₕ-rays” from alternating peaks geometrically locates the point of perspective (C), confirming that even in Newtonian mechanics, unresolved causal depth is encoded in exact symmetry conflict.

This is not analogy. It is identity : the same law governs a spinning nut on the ISS and the fate of Schrödinger’s cat.

1. Core Claim (unchanged, strengthened)

Superposition does not mean “both states exist”.  
It means: the causal decision is made — but its depth  (distance from observation) is hidden.

There is no wavefunction collapse.  
There is only unresolved causal depth, quantified by exact geometric constants.

2. Exact Constants — Analytical + Numerical

All constants derive from angles π/3 (60°), π/4 (45°), π/5 (36°), π/8 (22.5°).  
No approximations. No fitting.

• Alpha-caliber (α) — intensity bound for asymmetric events:
  α = [sin(π/3) − sin(π/4)] / [sin(π/2) − sin(π/3)]
    = (√3 − √2) / (2 − √3)
    = (√3 − √2)(2 + √3)
    = 2√3 + 3 − 2√2 − √6                  ◼
  α ≈ 1.186184748058023

• Beta-caliber (β) — symmetry bound:
  β = [cos(π)